Подмассивы последовательных элементов

const aperture = (n, arr) =>
  n > arr.length
    ? []
    : arr.slice(n - 1).map((v, i) => arr.slice(i, i + n));

const findConsecutive = (arr, n) =>
  arr.slice(n - 1).map((v, i) => arr.slice(i, i + n));

aperture(2, [1, 2, 3, 4]); // [[1, 2], [2, 3], [3, 4]]
aperture(3, [1, 2, 3, 4]); // [[1, 2, 3], [2, 3, 4]]
aperture(5, [1, 2, 3, 4]); // []

findConsecutive([1, 2, 3, 4, 5], 2);
// [[1, 2], [2, 3], [3, 4], [4, 5]]